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EC-010 · Oxidation and Reduction Reactions in Corrosion July 26, 2026
EC TRACK · ELECTROCHEMISTRY & THE GALVANIC SERIES

Oxidation and Reduction Reactions in Corrosion

The matched pair behind every corroding pipe - oxidation and reduction, always running together, and the inversion that makes CP work.

Foundation ~10 minutes PDH/CEC eligible

Apply — three field-grounded problems

Match the pair, find the pair, lose the pair

Three short problems, all built from the matched pair you just learned — and all kept at the level you’d actually use on the job. In the first you match up the electrons in a sacrificial-anode reaction. In the second you find the anode and the cathode in the two kinds of cathodic protection. In the third you reason through what happens when protection quits on you. Read each setup, think it through, then click each step to compare with our working.

How to use this lesson. Read the setup. Think before you click. Each step reveals what we’d say.


Problem 1 · Match the electrons

The reaction that’s eating the anode

Setup. Picture the magnesium anode from the start of this module, doing its job in damp, aerated soil — slowly giving itself up to protect the line. Two half-reactions are running. The magnesium oxidizes: Mg → Mg²⁺ + 2e⁻. On the steel it’s protecting, oxygen reduction takes the electrons: O₂ + 2H₂O + 4e⁻ → 4OH⁻.

Put the two halves together into one balanced reaction — the reaction that’s actually consuming the anode. The one rule: every electron the magnesium gives up has to be used by the oxygen side.

Step 1 — match the electrons

Count what each side handles. Magnesium gives up 2 electrons per atom. Oxygen reduction takes 4 at a time. Those don’t match — so it takes two magnesium atoms to feed one oxygen reaction.

Two magnesiums: 2Mg → 2Mg²⁺ + 4e⁻
Oxygen side: O₂ + 2H₂O + 4e⁻ → 4OH⁻

Now it’s 4 electrons given and 4 electrons taken. Even.

Step 2 — add the halves together

Put them together and the electrons cancel — they never actually left the system, they just went from the magnesium to the steel.

2Mg + O₂ + 2H₂O → 2Mg(OH)₂

The magnesium ions and the hydroxide ions pair up into magnesium hydroxide. That’s the magnesium turning into corrosion product — the anode wearing away, exactly what we buried it to do.

Step 3 — name the two halves

Tag each half with OIL RIG. The magnesium side — losing electrons — is the oxidation. The oxygen side — gaining them — is the reduction. Two halves, locked together, two magnesiums for every oxygen.

It’s the same move we made with iron and oxygen back in the Read. Different metal, same idea: match the electrons, add the halves, and the ratio falls out on its own.

Match the electrons, then add the halves. Magnesium gives 2 and oxygen takes 4, so it’s two magnesiums per oxygen: 2Mg + O₂ + 2H₂O → 2Mg(OH)₂. The electrons set the ratio — you don’t pick it.


Problem 2 · Find the anode, find the cathode

Two ways to protect the same line

Setup. Same buried steel line, protected two different ways — the two kinds of cathodic protection you’ll run into. You don’t need to write any chemistry for this one. Just figure out, in each case, which piece of metal is corroding (the anode) and which is being protected (the cathode).

SETUP A · GALVANIC
Hardwaremagnesium anode
Wired tothe steel line
Powernone – natural
SETUP B · IMPRESSED CURRENT
Hardwarerectifier + groundbed
Wired tothe steel line
Powerrectifier (AC in)

For each setup: which piece is the anode (the one that corrodes), and which is the cathode (the protected steel)? And in one sentence — why is the steel protected?

Step 1 — the one idea behind both

Cathodic protection does one thing, two ways: it makes your steel the cathode. A cathode only runs reduction — electrons coming in — so the steel’s iron has no reason to give up its own. The oxidation gets shoved off the pipe and onto something else. Find that “something else” and you’ve found the anode.

Step 2 — Setup A: the magnesium anode

Anode: the magnesium. It’s more active than steel, so it corrodes on its own and feeds its electrons into the line.

Cathode: the steel — protected.

Why protected: the magnesium is handing the steel electrons for free, so the steel’s iron never has to give up any. The anode dissolves so the pipe doesn’t. (That’s the lump from the start of the module.)

Step 3 — Setup B: the rectifier

Anode: the groundbed out in the field, pushed by the rectifier.

Cathode: the steel — protected, same as before.

Why protected: there’s no sacrificial metal here — the rectifier takes wall power and pushes electrons onto the steel from outside. Same result: the steel runs reduction, and the corroding happens out at the groundbed instead of on your pipe.

Step 4 — the common thread

Galvanic or impressed current, the steel ends up doing the same thing: only reduction. One setup gets the electrons from a metal that’s happy to corrode; the other gets them from a rectifier. Either way, your structure is the cathode, and a cathode doesn’t lose metal.

Both kinds of cathodic protection do one thing: make the steel the cathode and move the corrosion somewhere you chose. Find what’s corroding and what’s protected, and any CP setup reads straight off the pair.


Problem 3 · When protection quits

The anode that quit

Setup. That buried line is protected by its magnesium anode, and for a couple of years the readings look good — the steel isn’t losing metal. Then a contractor’s mini-excavator, working an unrelated job nearby, catches the anode’s lead wire and snaps it clean underground. Nobody sees it happen. The line looks exactly the same from the surface.

No math here — just reason it through. (1) While the anode was connected, which metal was corroding, and why wasn’t the steel losing any? (2) The instant that lead wire snaps, what changes for the steel? (3) If you dig the line up a year later, what would you expect to find?

Step 1 — while the anode was hooked up

The magnesium was the one corroding. It oxidized and fed its electrons down the lead wire and into the steel. The steel sat there as the cathode, taking those electrons in.

Why didn’t the steel lose metal? Because its iron only oxidizes when it needs to let go of electrons — and the magnesium was supplying them from outside. With its electrons coming for free, the steel had no reason to give up any of its own. Protected.

Step 2 — the moment the wire snaps

The outside electron supply is gone. The steel is on its own again. With nothing feeding it electrons, the steel’s own iron goes right back to doing the oxidizing — Fe → Fe²⁺ + 2e⁻ starts running on the pipe wall again.

Nothing looks different at the surface. But from that moment, the pipe is corroding — quietly, with no anode covering for it anymore.

Step 3 — a year later in the ditch

You’d expect fresh corrosion on the steel — new pitting and metal loss that wasn’t there before — because the pipe has been an unprotected, bare anode for a year. And the magnesium would be frozen right where it was the day the wire broke; it stopped wearing away the moment the circuit opened, because it had nothing to feed anymore.

If anyone had taken a reading, the line would have flipped from protected to not — the day of the snap, not the day you dug it up.

Cathodic protection is just an outside electron supply. Cut it — a snapped lead, a dead rectifier — and the steel goes straight back to oxidizing. The matched pair never went anywhere; you were just feeding the cathode from outside. That’s why a broken anode lead is an emergency, not a paperwork problem.


What this Apply lesson was after. Three uses of one idea, all at field level. You matched the electrons in the reaction eating a magnesium anode. You found the anode and the cathode in the two kinds of cathodic protection and saw they do the same thing — leave the steel running only reduction. And you reasoned through what happens when the protection quits: cut the outside electrons, and the steel is right back to oxidizing.

The Quiz at the end of this module checks the core ideas with a mix of recall and recognition questions. After that, the Electrochemistry set moves on to ranking the metals — which one in a pair becomes the anode, and by how much. You’ve been calling the anode all module; next you’ll learn how to predict it.