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EC-009 · The Electrochemical Cell: Anodes, Cathodes, Electrolytes July 26, 2026
EC TRACK · ELECTROCHEMISTRY & THE GALVANIC SERIES

The Electrochemical Cell: Anodes, Cathodes, Electrolytes

The four parts of a corrosion cell, where the metal goes, and the reactions that drive it - the system every CP method works by interrupting.

Foundation ~10 minutes PDH/CEC eligible

Apply — three field-grounded problems

Find the cell, follow the current, name the fix

Three short problems, all built from the corrosion cell you just assembled. The first is a real field puzzle — a replacement joint that keeps failing — that you’ll solve by mapping the cell. The second puts numbers on the area-ratio effect and lands why a small coating defect is such bad news. The third walks three environments and asks which cathodic reaction is running in each. Read the setup, think it through, then click each step to compare with our working.

How to use this lesson. Read the setup. Think before you click. Each step reveals what we’d say.


Problem 1 · The joint that keeps failing

“They don’t make steel like they used to”

Setup. A gathering line that’s been in the ground about 30 years develops a leak at a single joint — external corrosion, a pit that’s finally gone through the wall. The crew digs it up, cuts out the corroded section, and welds in a short replacement joint — a ‘pup’ — of bright new steel. They wrap the weld, backfill, and move on. This line has never had cathodic protection. About eighteen months later, that same location is leaking again — the new steel this time, not the decades-old pipe on either side of it. The foreman looks at it and says, “They don’t make steel like they used to.”

Is the foreman right? Map the corrosion cell at that joint, explain why the brand-new steel corroded faster than the 30-year-old pipe around it, and say what would actually keep it from happening a third time.

Step 1 — map the four parts of the cell

The moment that bright joint was welded in and backfilled, a corrosion cell was set up. Lay the four parts on it:

  • Anode — the new pup, the bright-steel joint just welded in. This is the metal that’s leaving.
  • Cathode — the large run of old, scaled pipe on both sides of the weld.
  • Electrolyte — the moist soil packed around the line.
  • Metallic path — the pipe itself. The new joint was welded into the old line, so it’s all one continuous piece of steel; electrons move freely between the joint and the old pipe.

Four parts, all present, all connected. The cell ran from day one.

Step 2 — why the new steel goes first

Two things stack up against that new joint, and both come straight from this module.

Bright steel is more active than old steel. Freshly milled and ground steel gives up electrons more readily than steel that’s spent 30 years building a settled layer of mill scale, rust, and oxide. The old surface behaves like the more “noble” metal — so in this cell, the old pipe takes the cathode role and the new joint takes the anode role.

Small anode, large cathode. The new pup is just a few feet of pipe. The cathode is essentially the rest of the line. That’s the area-ratio effect from the Read: the corrosion current the whole old line can drive gets funneled onto one small fresh joint. Concentrated current density, fast and deep metal loss — right where the new steel is.

The old pipe, meanwhile, is now the cathode. It’s actually being protected — at the new joint’s expense.

Step 3 — is the foreman right?

No. The steel isn’t the problem. Take that exact same new joint and put it somewhere it lands as the cathode, and it would outlast everything around it. The joint didn’t fail because of what it was made of; it failed because of where it sat in the cell — a small, fresh, bare anode wired to a large old cathode, with no protection on the line.

“They don’t make steel like they used to” is the wrong read. The right read is: “We welded bare, active steel into an old line and didn’t do anything to break the cell.” That’s not a metallurgy story. It’s the corrosion cell doing exactly what the physics says it will.

Step 4 — what actually stops it

Go back to the four-part rule: break any one part and the cell stops. For a buried line, the practical move is cathodic protection.

  • Apply CP. Flood the whole line — new joint included — with electrons from an outside source so the entire structure becomes the cathode. No spot on the pipe is left as the anode. This is the real fix.
  • Coat the new joint well. A good coating shrinks the bare metal area. It helps, but a bare holiday in an otherwise coated joint re-creates a small-anode problem — so coating goes with CP, not instead of it.
  • Isolate it — cutting the metallic path with isolation hardware is a fourth-part attack, but mid-line isolation usually isn’t practical and tends to just move the cell. CP is the standard answer.

Bottom line: don’t weld bright bare steel into an old line and walk away. Either break the cell with CP or you’ll be back digging up the same joint.

When the new part keeps failing, suspect the cell, not the steel. A small, fresh, bare anode tied to a big old cathode is a recipe for fast, localized loss — and cathodic protection is how you turn the whole line into the cathode instead.


Problem 2 · Put numbers on the area ratio

A nearly perfect coating — and why the holidays still matter

Setup. A coated steel line runs 1 mile of 8-inch pipe (outside diameter 8.625 in). An inspection finds the coating is in great shape — about 99.9% intact, with only scattered small holidays adding up to roughly 0.1% of the surface as bare metal. The office figures a coating that good means there’s nothing to worry about. You’re not so sure.

Treating the bare metal as the anode and the rest of the line as the cathode, work out the cathode-to-anode area ratio. Then explain what that ratio does to the corrosion at those bare spots — and to where you’d point your inspection effort.

Step 1 — how much pipe surface are we talking about

Start with the total outside surface area of the line. Surface area of a pipe is circumference times length.

Outside diameter = 8.625 in
Circumference = π × 8.625 in ≈ 27.1 in
Length = 1 mile = 5,280 ft = 63,360 in
Surface area = 27.1 in × 63,360 in
    ≈ 1,717,000 in² ≈ 11,920 ft²

So there’s roughly 11,920 square feet of pipe surface on this one-mile run.

Step 2 — split it into anode and cathode, and take the ratio

The coating is 99.9% intact, so 0.1% of that surface is bare. The bare metal is the anode; the rest acts as the cathode.

Bare anode = 0.1% of 11,920 ft² ≈ 11.9 ft²
Cathode = 99.9% of 11,920 ft² ≈ 11,908 ft²

Cathode : anode = 99.9 : 0.1 ≈ 1,000 : 1

The ratio doesn’t even depend on the size of the pipe — 99.9 to 0.1 is about 1,000 to 1 on any line with that coating condition. About twelve square feet of bare steel is wired to roughly twelve thousand square feet of cathode.

Step 3 — what a 1,000:1 ratio does to the bare spots

All the corrosion current that the big cathode drives has to leave the structure through the anode — through that 0.1% of bare metal. Squeeze the same current through a thousandth of the area and the current density at the bare spots jumps by roughly the same factor.

Current density at the anode
  ≈ 1,000 × the average over the whole pipe

That’s the trap in “the coating is 99.9% good.” The coating didn’t make the corrosion go away — it concentrated it. Those few small holidays can corrode far faster and deeper than the same bare metal would on a totally uncoated pipe, because on the bare pipe the loss spreads out, and here it’s funneled to a pinpoint.

Step 4 — where that points your inspection effort

The lesson for the field is the opposite of the office’s first take:

  • The small defects are the priority, not an afterthought. On a well-coated line, the worst corrosion hides at the few coating holidays — that’s exactly where the current density is highest.
  • A great coating earns its keep with CP, not without it. The same math that concentrates corrosion also means the line needs very little CP current to protect that small bare area — coating and CP work as a pair.
  • “Percent intact” can mislead. 99.9% sounds like nothing to worry about; the 1,000:1 ratio is what tells the real story.

Small anode, large cathode, concentrated metal loss. A nearly perfect coating doesn’t remove the corrosion — it funnels it onto the few bare spots. That’s why a tiny holiday matters far more than its size suggests, and why those defects are where the inspection effort belongs.


Problem 3 · Which reaction is running

The cathodic reaction across three environments

Setup. The anodic reaction is the same everywhere a steel structure corrodes — iron dissolving, Fe → Fe²⁺ + 2e⁻. What changes from site to site is the reaction at the cathode that uses up those electrons. Here are three buried-structure environments:

SITE A
Soilsandy
Drainagewell-drained
Oxygenplenty
pH6.8
SITE B
Soilmine-impacted
Drainagerunoff
Oxygenpresent
pH3.5
SITE C
Soilwaterlogged clay
Drainagesealed, saturated
Oxygenstarved
pH6.5

For each site, name the cathodic reaction that dominates and write it out. Then give the field sign you’d expect to go with each.

Step 1 — the two cathodic reactions and when each runs

From the Read, the cathode runs one of two reactions, and the environment picks the winner:

  • Oxygen reductionO₂ + 2H₂O + 4e⁻ → 4OH⁻ — runs when there’s oxygen at the surface and the environment is roughly neutral to alkaline.
  • Hydrogen evolution2H⁺ + 2e⁻ → H₂ — runs when it’s acidic (plenty of H+), or when oxygen has been shut out so oxygen reduction can’t.

So the two questions to ask any site: is there oxygen at the metal, and is it acidic?

Step 2 — call each site

Site A — oxygen reduction. Well-drained sandy soil with plenty of oxygen, near-neutral at pH 6.8. Oxygen is available and it’s not acidic, so the cathode runs O₂ + 2H₂O + 4e⁻ → 4OH⁻. This is the everyday case for most buried pipe.

Site B — hydrogen evolution. pH 3.5 is strongly acidic — H+ is everywhere. The cathode runs 2H⁺ + 2e⁻ → H₂, and it runs hard. This is an aggressive environment.

Site C — hydrogen evolution. The pH is near neutral, but the soil is waterlogged and sealed off, so oxygen can’t reach the metal. With oxygen reduction starved out, the cathode falls back on 2H⁺ + 2e⁻ → H₂. Note this is exactly the kind of low-oxygen spot that goes anodic in a differential-aeration cell — the oxygen-starved metal does the corroding.

Step 3 — the field sign at each
  • Site A (oxygen reduction): the cathodic areas turn alkaline and tend to pick up chalky calcium/magnesium scale; the cathode itself looks comparatively clean. Corrosion shows up at the separate anodic spots as pitting.
  • Site B (hydrogen evolution, acid): aggressive general attack, and you may see hydrogen gas — fine bubbling — at cathodic sites. Low pH plus bare steel is a fast-loss situation.
  • Site C (hydrogen evolution, oxygen-starved): attack concentrated in the sealed, wet, low-oxygen pockets — under deposits, under disbonded coating, at the bottom of the wet zone. These are the spots that quietly go anodic while better-aerated metal nearby stays clean.

One reaction never changed through all three: the anode, always Fe → Fe²⁺ + 2e⁻. Iron leaving is iron leaving. What the environment decides is the cathodic partner — and that’s the reaction a CP system has to outcompete.

The anode reaction is always iron dissolving. The cathode reaction depends on the site: oxygen reduction where there’s oxygen and it’s near neutral, hydrogen evolution where it’s acidic or oxygen has been shut out. Read the environment, know the reaction.


What this Apply lesson was after. Three uses of one idea. You solved a real field failure — the joint that keeps leaking — by mapping the corrosion cell and reading off the fix, instead of blaming the steel. You put numbers on the area ratio and saw why a nearly perfect coating still demands attention at its few bare spots. And you read three environments for which cathodic reaction is running, while the anodic reaction stayed exactly the same at all three.

The Quiz at the end of this module checks the same ideas with a mix of recall and recognition questions. After that, the Electrochemistry set continues into EC-010, where the anodic and cathodic reactions you’ve been naming get treated as a matched pair — oxidation and reduction, always running together. The cell you built here is the frame the rest of the set hangs on.