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EC-003 · Voltage, Current, and Resistance in DC Systems July 26, 2026
EC TRACK · ELECTRICAL BASICS FOR CP

Voltage, Current, and Resistance in DC Systems

What V, I, and R actually are — and how each is measured in the field.

Foundation ~10 minutes PDH/CEC eligible

Apply — three problems

Read the meter, name the quantity, make the call.

Three problems. The point isn’t arithmetic — it’s recognizing what each instrument setup is actually measuring, what reading means what, and how to put two or three readings together into a system diagnosis. Work through each one before you click. Match your reasoning to ours.

How to use this lesson. Read the setup. Think it through. Each step reveals our reasoning. If your answer doesn’t match, the steps are there to compare against.


Problem 1 · Identify the quantity

Three setups, three readings — name what’s being measured.

Setup. A junior tech walks up to three different instruments at the same site and reads each one. The three setups:

Setup A Cu/CuSO4 half-cell pressed into moist soil next to a buried pipe. Multimeter on V DC. Black lead from the meter to the half-cell, red lead to a header bond at the test station. Display: −1.05 V.
Setup B Multimeter on mV DC, leads across a calibrated 0.01 Ω rectifier shunt. Display: 180 mV.
Setup C Soil resistivity meter (4-pin Wenner). Four pins driven 5 ft apart in a line. Display: 4,800 Ω-cm.

For each setup: which of the three quantities (V, I, R) is being measured, what does the reading represent, and what does it tell you about the system at that point?

Setup A — what’s being measured

Quantity: Voltage (V).

What it represents: the structure-to-soil potential at this test station — the difference in electrical potential between the pipe and the soil, referenced through the Cu/CuSO4 half-cell.

What it tells you: the pipe is at −1.05 V Cu/CuSO4 — more negative than the −0.85 V criterion. The pipe meets criterion at this location.

Setup B — what’s being measured

Quantity: Current (I) — measured indirectly via a voltage drop across a known resistance.

What it represents: the rectifier output current. The voltmeter reads the IR drop the shunt makes visible. Apply Ohm’s Law (EC-002):

Convert to base units first: 180 mV → 0.18 V.

I = V ÷ R = 0.18 V ÷ 0.01 Ω = 18 A

What it tells you: the rectifier is putting 18 A into the system right now. Compared to design current and prior readings, that says whether the source side is performing.

Setup C — what’s being measured

Quantity: Resistance (R) — specifically soil resistivity, an intrinsic property of the soil itself.

What it represents: the bulk electrical resistivity of the soil, expressed in ohm-centimeters (Ω-cm), at the location and depth corresponding to the 5-ft pin spacing. (Wenner-method depth roughly equals pin spacing.)

What it tells you: the soil at this location is moderately conductive. Around 4,800 Ω-cm sits in the middle of the typical pipeline-corridor range (1,000–30,000 Ω-cm). This is a design input — it drives anode-to-soil resistance calculations and groundbed sizing — not a direct measure of system health.

Three setups, three different quantities, three different stories. The instrument and the test setup tell you what’s being measured before the number does. V requires a reference. I needs a known resistance to be inferred from a voltage drop. R demands a purpose-built tool — you don’t measure soil resistivity with a regular ohmmeter.


Problem 2 · Read and diagnose

A structure-to-soil potential reading on a section that “should be fine.”

Setup. You’re walking a section of pipeline that the design report shows is well-coated, with two galvanic anode groups serving the section. At one test station, the structure-to-soil reading is −0.78 V Cu/CuSO4. The system criterion is −0.85 V or more negative.

What does that reading mean, and what should you do next?

Step 1 — read the number against the criterion

The criterion is −0.85 V or more negative (i.e., −0.85 V, −0.90 V, −1.00 V, etc., all meet criterion). The reading is −0.78 V — less negative than −0.85 V. So this location does not meet criterion as read.

The structure is under-protected at this point relative to the standard. That doesn’t automatically mean corrosion is occurring — the criterion includes safety margin — but it does mean the system is not delivering the protective state the design intended at this location, and that’s worth resolving.

Step 2 — what could be causing it

Several possibilities, none of them mutually exclusive:

  • No CP installed (or disconnected) at this section. A −0.78 V reading sits close to the natural-state range for unprotected steel in moist soil. Worth verifying the system here is actually energized and that the bond to this section is intact before chasing the other causes.
  • Galvanic anode consumption. The anodes serving this section are doing the work of staying negative; as they consume, their output drops and the structure drifts toward less-negative readings. This is the most common cause on long-served galvanic systems.
  • Drier soil than design assumed. Higher soil resistivity means more anode-to-soil resistance, which means less current onto the structure, which means less negative readings.
  • Coating damage near this test station. A localized coating defect would mean more current is needed to protect that exposed area than the original design budgeted for. Other test stations might still meet criterion while this one drifts.
  • Foreign-line interference or stray current. Less common but possible — another structure or DC source nearby could be pulling protective current away.
Step 3 — what to do next
  • Read more locations. Is this isolated to one test station or is the whole section drifting? If isolated, the cause is local. If widespread, anode consumption or design assumptions changing are more likely.
  • Check the anode bond currents. If a galvanic anode group is putting out less current than design (say, 50 mA today vs. 250 mA in the original commissioning report), that’s a strong signal toward anode consumption.
  • Check the trend. The history matters. A single −0.78 V reading is one data point; six months of progressively less-negative readings at this station is a story.
  • Document and elevate. A reading that misses criterion gets logged, gets a planned action, and gets re-read on the next visit. Not protected today doesn’t mean abandoned today — it means we know something about the system we didn’t know yesterday, and we have a plan.

The reading is just a number until you put it next to the criterion. The criterion turns the number into a status. The status turns the status into the next action. That chain — number → criterion → status → action — is the work of CP.


Problem 3 · Synthesize

Three readings at one site, one health picture.

Setup. One CP system on a 12-mile section of distribution. You take three readings on a routine bi-monthly check:

Reading A — Structure-to-soil potential at TS-04 (mid-line) Cu/CuSO4, half-cell in moist soil, multimeter on V DC: −0.86 V
Reading B — Rectifier output Your multimeter on volts DC at the output terminals reads 26 V. Across the rectifier’s “50 mV = 10 A” shunt, your multimeter on millivolts DC reads 36 mV.
Reading C — Design baseline (commissioning report) Vdesign = 22 V, Idesign = 8 A, Rdesign,total = 2.75 Ω. Structure-to-soil at TS-04 at commissioning: −0.95 V.

What’s the system telling you, and what would you flag for follow-up?

Step 1 — convert the shunt reading to current

The shunt rating is “50 mV = 10 A” — a 0.005 Ω shunt (50 mV ÷ 10 A → 0.05 V ÷ 10 A = 0.005 Ω in base units).

Convert the live reading to base units first: 36 mV → 0.036 V.

I = V ÷ R = 0.036 V ÷ 0.005 Ω = 7.2 A

Today’s rectifier output current: 7.2 A.

Step 2 — back out today’s total circuit resistance

Apply Ohm’s Law solve-for-R (the move you walked through in EC-002):

Rtotal = V ÷ I = 26 V ÷ 7.2 A ≈ 3.61 Ω

Compare to design: design Rtotal was 2.75 Ω. Today’s Rtotal is 3.61 Ω — about 0.86 Ω higher than design. That’s a meaningful climb (≈31% higher).

Step 3 — read the structure-to-soil against criterion

−0.86 V Cu/CuSO4 at TS-04 today. The −0.85 V criterion is met — barely. Compare against commissioning’s −0.95 V at the same test station: today’s reading is 0.09 V less negative than at commissioning. The system is meeting criterion but trending in the wrong direction.

Step 4 — what the three readings together say

The story the readings tell when read together:

  • Source side: Rectifier voltage has climbed from 22 V (design) to 26 V — the system is auto-tapping up to compensate for something. Current has dropped from 8 A (design) to 7.2 A. That combination is the signature of rising total circuit resistance.
  • Resistance side: Rtotal has climbed from 2.75 Ω to 3.61 Ω. Most likely candidates: anode consumption (lifting parallel-array R), drier soil (increasing anode-to-soil resistance), or a connection drift on the series side.
  • Protected side: The structure-to-soil at TS-04 has drifted from −0.95 V at commissioning to −0.86 V today. Still meeting criterion (barely), but the headroom against criterion is shrinking. The rectifier has been compensating — but it’s nearly out of voltage headroom (most rectifiers max at 24 V, 36 V, or 50 V; 26 V says we’re well into the rectifier’s output range).

This is a system that’s still working, but is slowly losing margin. Not an emergency. Definitely a flag for follow-up.

Step 5 — what would you flag
  • Trend the source readings. Pull the last 6–12 months of rectifier V/I logs. If V has been climbing month over month while I drops, we’re watching a slow groundbed degradation play out.
  • Walk more test stations. Read structure-to-soil at TS-01, TS-02, TS-03, TS-05, TS-06. If TS-04 is the lowest reading on the line, the issue is local. If readings are uniformly tight, it’s the whole groundbed.
  • Inspect the groundbed. If anode consumption is suspected, schedule a groundbed inspection: visual, electrical, and ideally individual anode current readings if the array has accessible per-anode shunts.
  • Plan ahead, not in panic. 26 V on a system designed at 22 V means we have voltage left. But not unlimited. Knowing the trajectory now lets you plan a groundbed supplement or replacement before criterion is missed — instead of after.

One reading tells you status at a point. Three readings tell you the source state, the resistance state, and the protective state — and Ohm’s Law lets you derive a fourth piece (total R) from two of them. None of that synthesis happens unless you can name what each reading is. That’s why we distinguish V, I, and R.


Three problems, three different jobs the same trio of quantities does — identify the measurement, read the value against criterion, synthesize across multiple readings into a system picture.

You’ll do this same kind of work every time you walk a CP system. The instruments are different at every test station. The numbers change every visit. What stays the same is the discipline: name the quantity, know what it represents, compare it to the right reference, and read it alongside what else the system is telling you.

Up next: a quiz to confirm V, I, and R are wired in.