RCS Training RCS Training
G Guest
EC-014 · Polarization Fundamentals: Types and Effects August 24, 2026
EC TRACK · ELECTROCHEMISTRY & THE GALVANIC SERIES

Polarization Fundamentals: Types and Effects

What a potential does once current is actually flowing - the three real kinds of polarization, the one that only looks like it on a meter, and where the 100 mV criterion comes from.

Foundation ~10 minutes PDH/CEC eligible

Apply · three problems

What the numbers are telling you

Three problems, three parts of the job. First you diagnose — three situations, and in each one a different kind of polarization is doing the talking. Then you explain a seasonal swing that looks alarming on a work order and is not. Last you run the arithmetic on an inherited file and decide not just whether a line passes, but how much room it actually has.

Work each one before you open the reveal. The reveals walk the reasoning — the point isn’t the answer, it’s the path.

Ground rules. Everything you need came from the Read lesson. Carbon steel moves roughly one decade — one factor of ten in corrosion rate — per 100 mV of polarization shift. So: decades = shift ÷ 100 mV, and the rate cut is 10 raised to that power. Native potentials for ordinary steel in soil run about −0.55 to −0.65 V vs. copper sulfate. Round sensibly; nobody needs three decimals at a test station.

Problem 1

Three situations, three mechanisms

The morning. Three unrelated jobs, three sets of numbers, and in every one of them something is polarizing — but not the same something. Name which kind is dominating each, and say what in the data told you.
SITUATION A — COATED BURIED LINE, ICCP
On-potential (current flowing)−1.15 V
Instant-off (interrupted)−0.86 V
Difference?
SITUATION B — RECTIFIER OUTPUT STEPPED UP
Output raised, first steppotential moves
Output raised againmoves less
Output raised a third timebarely moves
SITUATION C — FRESHLY BARED STEEL, STAGNANT FRESH WATER
Protection appliedt = 0
Potential at final valueseveral hours later

For each situation: which kind of polarization dominates, and what is the diagnostic tell?

Show solution

Situation A — resistance drop, which is not polarization at all. The two readings are taken seconds apart on the same steel, so nothing chemical had time to change.

1.15 V − 0.86 V = 0.29 V = 290 mV of IR drop

That 290 mV is voltage across the soil between the pipe and your reference cell, and it vanishes the instant the current does. The tell is speed: anything that disappears inside an interrupter cycle was electrical, not chemical. The honest number for this pipe is −0.86 V, not −1.15.

Situation B — concentration polarization. More current is being supplied and less shift is coming back. The cathodic reaction has run out of something to react with — almost always oxygen, arriving through the soil more slowly than the surface consumes it.

The tell is diminishing returns on added output. Nothing is broken. You have reached the delivery limit, and more current buys almost nothing but a bigger power bill and a harder-working anode bed.

Situation C — activation polarization. Fresh, clean steel with plenty of reactant available and no delivery problem, taking hours to settle.

The tell is a slow build with no shortage. The reaction itself is the bottleneck — charge transfer at the surface is sluggish, and it costs potential to push it faster. Reading this system the same afternoon it was energized would understate it badly.

Three mechanisms, and none of them was diagnosed from a single number. Each one was read out of what the numbers did — over one second, over three rectifier steps, over several hours.

Problem 2

The line that drinks more in August

The work order. A line in moderate-resistivity sandy soil. Someone has flagged the current demand as erratic and asked whether the rectifier needs adjusting.
CURRENT DEMAND — SAME LINE, TWO SEASONS
Summer (warm, dry, well-aerated)8 mA/m²
Winter (cool, saturated)3 mA/m²
Rectifier settingunchanged

Explain the swing in polarization terms — then answer the question that was actually asked: does this justify adjusting the rectifier?

Show solution

The mechanism. Nearly a threefold swing, and the ground did all of it.

  • Summer: dry, warm, well-aerated soil delivers oxygen to the steel freely. The cathodic reaction runs hard, and it takes more current to hold the same polarization. Warmth speeds the reaction further.
  • Winter: saturated soil chokes off oxygen delivery. Concentration polarization increases, the cathodic reaction slows on its own, and less applied current achieves the same shift.

Same steel, same coating, same rectifier. The environment moved, so the demand moved with it.

The answer to the question asked: not on this data. Current demand is an input, not a verdict. The number that decides whether this line is protected is its polarized potential — and nobody reported one. A line drawing 8 mA/m² in July may be holding its shift perfectly well; a line drawing 3 in January may not be.

Go get an instant-off reading in each season before touching an output knob. Chasing the current number is how a well-protected line gets adjusted into over-protection — and past a point you trade corrosion for coating disbondment and hydrogen at the steel surface.

Current demand tells you what the ground is asking for. Polarized potential tells you whether the steel is getting it. Only one of those is the criterion.

Problem 3

How much room does it actually have

The file. A crew hands you readings from a buried line and asks whether it meets the polarization-shift criterion. It does. The more useful question is the one nobody asked.
STATION 14+80 — INHERITED READINGS
Native (depolarized, no CP)−0.55 V
Polarized (instant-off, CP on)−0.71 V
Criterion in use100 mV shift

Find the polarization shift, convert it to a corrosion-rate cut, and say how comfortable this station really is.

Show solution

Step 1 — the shift.

0.71 V − 0.55 V = 0.16 V = 160 mV

Step 2 — convert to decades.

160 mV ÷ 100 mV per decade = 1.6 decades

Step 3 — convert to a rate cut.

10 ^ 1.6 = about 40

The answer. A 160 mV shift clears the 100 mV criterion with room to spare, and the steel is losing roughly one-fortieth of what it would lose bare.

And the question nobody asked. Forty times is real protection — better than a station scraping in at 120 mV, and a long way short of one holding 350. That is the judgment the arithmetic buys you. “Does it pass” is a yes-or-no that hides the difference between a station with margin and a station with none. Sixty extra millivolts of shift on this line would roughly quadruple the protection again, and that is worth knowing before the next dry summer raises what the ground is asking for.

The criterion is a floor. The arithmetic is what turns a pass into a picture of how much room you are working with.


That is the set. Diagnose which polarization is talking, explain what the ground is doing to your current demand, and convert a shift into what it is actually worth in metal saved.

Every CP survey you run from here is some version of these three questions. The numbers change; the reasoning does not.